quadratics
Simply the most useless maths topic ever. i dont think ill ever be at the shops, looking to buy $2 of bananas and for some reason need to calculate where the bloody parabola is meant to go on the x and y axis. useless. id rather stick my nuts underQuadratics
Quadratics
the neatest thing in math ever !!!! you see by using quadratics to solve equations, your avoiding the guess and check method!!!! quadratics are set to zero and have two answers!!!!
Example:
Next year, on the regents, make sure you use some quadratics in word probelms, so that you can avoid the guess and check method, WHICH IS STINKY!!!!!
Next year, on the regents, make sure you use some quadratics in word probelms, so that you can avoid the guess and check method, WHICH IS STINKY!!!!!
quasi quadratic
The Schrödinger's Cat of equations. Nobody really knows what it is or what it means. The easiest way to commit an algebraic atrocity.
Example:
What the hell is a quasi quadratic?
What the hell is a quasi quadratic?
quadratic formula
x = -b plus or minus the square root of (b^2 - 4ac) all divided by 2a. Used for quadratic equations where you can't factor. the equation is ax^2 + bx + c.
Quadratic Formula
The best method of solving a quadratic. When your equation is in the standard form of ax² + bx + c = 0, x = (-b ± √b² - 4ac) / 2a. It is far superior to both factoring and completing the square. The equation may look difficult, but all you have to do is plug in the coefficients and simplify!
Example:
A: I had to use the quadratic formula to solve that tricky problem.
B: Why didn't you just do that in the first place?
A: I had to use the quadratic formula to solve that tricky problem.
B: Why didn't you just do that in the first place?
Quadratic peinor
quadratic formula
A handy formula easily memorized by repetition. It is used in many instances, such as trying to find the roots of an equation, or solving an equation that will not factor with integers.
To solve using the Quadratic Formula:
In any equation
ax^2+bx+c,
The roots can be found by substituting into:
-b(+,-)sqrt(b^2-4ac)/2a
OR
Negative "B" plus or minus the square root of "B" squared minus 4(a)(c), all divided by 2(a).
To solve using the Quadratic Formula:
In any equation
ax^2+bx+c,
The roots can be found by substituting into:
-b(+,-)sqrt(b^2-4ac)/2a
OR
Negative "B" plus or minus the square root of "B" squared minus 4(a)(c), all divided by 2(a).
Example:
To solve using the Quadratic Formula:
In any equation
ax^2+bx+c,
The roots can be found by substituting into:
-b(+,-)sqrt(b^2-4ac)/2a
OR
Negative "B" plus or minus the square root of "B" squared minus 4(a)(c), all divided by 2(a).
EX:
Hm..
10x^2+13X-5
-13(+,-)sqrt(169+200)/20
>_>
In other words, by substituting the numbers in, you get 13(+,-)sqrt(369)/20.
As you may or may not have guessed, this gives you a very nasty number, which should be approximated and rounded to the nearest thousandth.
To solve using the Quadratic Formula:
In any equation
ax^2+bx+c,
The roots can be found by substituting into:
-b(+,-)sqrt(b^2-4ac)/2a
OR
Negative "B" plus or minus the square root of "B" squared minus 4(a)(c), all divided by 2(a).
EX:
Hm..
10x^2+13X-5
-13(+,-)sqrt(169+200)/20
>_>
In other words, by substituting the numbers in, you get 13(+,-)sqrt(369)/20.
As you may or may not have guessed, this gives you a very nasty number, which should be approximated and rounded to the nearest thousandth.
Quadratic Formula
A mildly long but sensible and useful equation. Typically used for solving for the two, one, or zero real values of X in a quadratic equation.